Pyramid Frustum Calculator: Volume & Base Areas

Find a square pyramid frustum's top area, bottom area, and volume from its top edge, bottom edge, and height, with exact step-by-step results.

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The pyramid frustum's three measures

A pyramid frustum is a square pyramid with its tip cut off by a plane parallel to the base — a smaller top square of edge aa and a larger bottom square of edge bb, joined by a tapering side of height hh. Given aa, bb, and hh, the top area, bottom area, and volume all follow:

A1=a2A2=b2A_1 = a^2 \qquad A_2 = b^2 V=h3(a2+ab+b2)V = \frac{h}{3}\left(a^2 + ab + b^2\right)

This is the simplest solid in its family: no π\pi anywhere (a square base, not a circle), and no square root anywhere in these three measures — unlike the plain square pyramid's slant height or the conical frustum's slant height, A1A_1, A2A_2, and VV are a plain rational expression in aa, bb, and hh.

Tip: The general frustum formula is V=h3(A1+A2+A1A2)V = \frac{h}{3}(A_1 + A_2 + \sqrt{A_1 A_2}), where A1,A2A_1, A_2 are the two base AREAS. For a square base, A1A2=a2b2=ab\sqrt{A_1 A_2} = \sqrt{a^2 b^2} = ab — giving a2+ab+b2a^2 + ab + b^2. Some references shorten this to "a+b+aba + b + \sqrt{ab}", but that shortcut is only valid when aa and bb ARE the areas already — plug in edge lengths there and the volume comes out wrong. This calculator always takes edge lengths, so it always uses a2+ab+b2a^2 + ab + b^2.

Worked example: a = 3, b = 6, h = 4

A1=32=9A2=62=36A_1 = 3^2 = 9 \qquad A_2 = 6^2 = 36 V=43(9+3×6+36)=43(63)=84V = \frac{4}{3}\left(9 + 3 \times 6 + 36\right) = \frac{4}{3}(63) = 84

Because a=3a = 3, b=6b = 6, and h=4h = 4 are all whole numbers, every measure here comes out EXACT — the volume needs no rounding at all.

Worked example: a = 0, b = 6, h = 4 (degenerates to a full pyramid)

A1=02=0A2=62=36A_1 = 0^2 = 0 \qquad A_2 = 6^2 = 36 V=43(0+0+36)=43(36)=48V = \frac{4}{3}\left(0 + 0 + 36\right) = \frac{4}{3}(36) = 48

With the top edge shrunk to a point, this is exactly a square pyramid with base edge 6 and height 4 — the volume formula V=h3(0+0+b2)=13b2hV = \frac{h}{3}(0 + 0 + b^2) = \frac{1}{3}b^2h matches the pyramid's own formula precisely.

Worked example: a = 1, b = 2, h = 1 (volume not a whole number)

A1=12=1A2=22=4A_1 = 1^2 = 1 \qquad A_2 = 2^2 = 4 V=13(1+1×2+4)=13(7)2.3333V = \frac{1}{3}\left(1 + 1 \times 2 + 4\right) = \frac{1}{3}(7) \approx 2.3333

Even though aa, bb, and hh are all whole numbers, the volume isn't — 33 doesn't divide h(a2+ab+b2)=7h(a^2+ab+b^2) = 7 evenly. The top and bottom areas, by contrast, are always exact whole numbers whenever aa and bb are, since squaring a whole number always stays whole.

Tip: Setting a=ba = b collapses the frustum into a plain box: V=h3(3a2)=a2hV = \frac{h}{3}(3a^2) = a^2h, the same volume formula as a rectangular prism (or cube, if h=ah = a too) — a quick sanity check for any frustum calculation.

Common mistakes

  • Using the area-only shorthand with edge lengths. V=h3(a+b+ab)V = \frac{h}{3}(a + b + \sqrt{ab}) is only correct when aa and bb are already the two base areas — with edge lengths, the correct term is a2+ab+b2a^2 + ab + b^2, not a+b+aba + b + \sqrt{ab}.
  • Forgetting the middle term abab. The volume is a weighted combination of both areas plus their geometric mean, not just A1+A2A_1 + A_2 — dropping abab understates the true volume.
  • Misspelling "frustum" as "frustrum." The correct spelling has no second "r" after the "t."

Where this shows up

  • Grain silos, plant pots, lampshades: any container with a square cross-section that tapers from a wide base to a narrower top (or vice versa) is a pyramid frustum — volume tells you capacity.
  • Sanity-checking against simpler solids: since a=0a = 0 gives a square pyramid and a=ba = b gives a rectangular prism, you can always verify a frustum calculation by checking it against one of those two familiar shapes.

A pyramid frustum is a square pyramid truncated parallel to its base — knowing the top edge, bottom edge, and height is always enough to find the top area, bottom area, and volume, with the square pyramid and the rectangular box sitting at its two limiting cases.

Frequently asked questions

What is the formula for the volume of a pyramid frustum?
With top edge a, bottom edge b, and height h: top area A1 = a², bottom area A2 = b², and volume V = (h/3)(a² + ab + b²). All three come from a square-base frustum's edge lengths, not its base areas.
Why does the volume use a² + ab + b², not a + b + √(ab)?
The general frustum formula is V = (h/3)(A1 + A2 + √(A1·A2)), where A1 and A2 are the two base AREAS. For a square base, A1 = a² and A2 = b², so √(A1·A2) = √(a²b²) = ab — giving a² + ab + b². The shorthand a + b + √(ab) only works when a and b themselves are already the areas, never when they're edge lengths.
What happens when the top edge a is 0?
The frustum degenerates to a full square pyramid: the top square shrinks to a point, the top area becomes 0, and the volume formula reduces to V = (1/3)b²h — exactly the square pyramid's own volume formula, with b playing the role of the pyramid's base edge.
What happens when the top edge a equals the bottom edge b?
The frustum becomes a plain rectangular box: V = (h/3)(a² + a² + a²) = (h/3)(3a²) = a²h, since the two parallel faces are now congruent squares connected by a prism, not a taper.
Does the volume always come out to a whole number when a, b, and h are whole numbers?
No — V = h(a² + ab + b²)/3 is only a whole number when 3 divides h(a² + ab + b²) evenly. For example, a = 1, b = 2, h = 1 gives V = 7/3 ≈ 2.3333, even though every input is a whole number.
What is a pyramid frustum?
It's a square pyramid with its tip sliced off by a plane parallel to the base, leaving two square ends of different edge lengths (a smaller top edge a, a larger bottom edge b) joined by 4 trapezoidal side faces. Truncated grain silos, plant pots, and lampshades with square cross-sections are everyday frustum shapes.
How is the pyramid frustum related to the square pyramid and the conical frustum?
A pyramid frustum generalizes the square pyramid: setting a = 0 gives back the full pyramid. It's also the square-base counterpart of the conical frustum, which uses the same (h/3)(A1+A2+√(A1A2)) formula with circular base areas instead.

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